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Real-World Applicationshard
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A beam deflection y(x)y(x)y(x) is governed by d4ydx4=1\frac{d^4y}{dx^4} = 1dx4d4y​=1. With boundary conditions y(0)=0,y′(0)=0,y′′(L)=0,y′′′(L)=0y(0)=0, y'(0)=0, y''(L)=0, y'''(L)=0y(0)=0,y′(0)=0,y′′(L)=0,y′′′(L)=0, what is the deflection at x=Lx=Lx=L?