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Differential Equationshard
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A chemical reaction follows the rate equation dcdt=−k1c+k2(c0−c)2\frac{dc}{dt} = -k_1 c + k_2 (c_0 - c)^2dtdc​=−k1​c+k2​(c0​−c)2. If k1k_1k1​ and k2k_2k2​ are positive constants, how does the complexity of the solution change if we set k2=0k_2 = 0k2​=0?