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Derivativeshard
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A particle moves such that its position x(t)x(t)x(t) satisfies x(t)=∫0t21+u3 dux(t) = \int_{0}^{t^2} \sqrt{1 + u^3} \, dux(t)=∫0t2​1+u3​du. Determine the velocity v(t)=dxdtv(t) = \frac{dx}{dt}v(t)=dtdx​ at t=2t = 2t=2.