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Recursionmedium
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A recurrence relation is given by an=5an−1−6an−2a_n = 5a_{n-1} - 6a_{n-2}an​=5an−1​−6an−2​. If the general solution is an=c1(2n)+c2(3n)a_n = c_1(2^n) + c_2(3^n)an​=c1​(2n)+c2​(3n), what are the constants c1c_1c1​ and c2c_2c2​ given a0=1a_0 = 1a0​=1 and a1=4a_1 = 4a1​=4?