A researcher plans a survey on student satisfaction with campus dining. She needs a 95% confidence level, a margin of error of $E = 0.06$, and estimates the standard deviation is $\sigma = 0.8$. Using the formula $n = \left(\frac{z^* \cdot \sigma}{E}\right)^2$ where $z^* = 1.96$, what is the minimum sample size (round to the nearest integer)?