Real-World Applicationshard
0:00.0

A satellite is in an elliptical orbit around Earth with eccentricity e=0.5e = 0.5 and orbital period T=8T = 8 hours. Kepler's Equation relates the eccentric anomaly EE to the time tt from periapsis by M=E−esin(E)M = E - e \\sin(E), where M=frac2pitTM = \\frac{2\\pi t}{T} is the mean anomaly. How many hours after passing periapsis does the satellite reach an eccentric anomaly of E=fracpi2E = \\frac{\\pi}{2}?