A sequence has the general solution an=c1⋅2n+c2⋅3na_n = c_1 \cdot 2^n + c_2 \cdot 3^nan=c1⋅2n+c2⋅3n. Given a0=5a_0 = 5a0=5 and a1=12a_1 = 12a1=12, find c1c_1c1.
c1=3c_1 = 3c1=3
c1=2c_1 = 2c1=2
c1=−3c_1 = -3c1=−3
c1=1c_1 = 1c1=1