$2^{10} - \binom{10}{2} - \binom{10}{1} - \binom{10}{0}$

$\binom{10}{3} + \binom{10}{4} + \dots + \binom{10}{10}$

$2^{10} - 1$

$\sum_{k=3}^{10} \binom{10}{k}$