A transformation TTT is given by T(x,y)=(x+2,y−3)T(x, y) = (x+2, y-3)T(x,y)=(x+2,y−3). Is TTT invertible, and if so, what is T−1T^{-1}T−1?
Invertible, T−1(x,y)=(x−2,y+3)T^{-1}(x, y) = (x-2, y+3)T−1(x,y)=(x−2,y+3)
Invertible, T−1(x,y)=(x+2,y−3)T^{-1}(x, y) = (x+2, y-3)T−1(x,y)=(x+2,y−3)
Invertible, T−1(x,y)=(x−3,y+2)T^{-1}(x, y) = (x-3, y+2)T−1(x,y)=(x−3,y+2)
Not invertible