Add: 2x−1+3x2−1\dfrac{2}{x - 1} + \dfrac{3}{x^2 - 1}x−12+x2−13.
2x−5(x−1)(x+1)\dfrac{2x - 5}{(x-1)(x+1)}(x−1)(x+1)2x−5
2x+5(x−1)(x+1)\dfrac{2x + 5}{(x-1)(x+1)}(x−1)(x+1)2x+5
2(x+1)\dfrac{2}{(x+1)}(x+1)2
5(x−1)(x+1)\dfrac{5}{(x-1)(x+1)}(x−1)(x+1)5