Add: 2xx2−1+1x+1\dfrac{2x}{x^2 - 1} + \dfrac{1}{x + 1}x2−12x+x+11.
2x+x−1x2−1=3x−1(x−1)(x+1)\dfrac{2x + x - 1}{x^2-1} = \dfrac{3x - 1}{(x-1)(x+1)}x2−12x+x−1=(x−1)(x+1)3x−1
x+1x2−1\dfrac{x + 1}{x^2-1}x2−1x+1
3x−1(x−1)(x+1)\dfrac{3x - 1}{(x-1)(x+1)}(x−1)(x+1)3x−1
3x+1(x+1)(x−1)\dfrac{3x + 1}{(x+1)(x-1)}(x+1)(x−1)3x+1