Differential Equationshard
0:00.0

An autonomous equation dydt=f(y)\frac{dy}{dt} = f(y) has equilibrium solutions at y=1,0,1y = -1, 0, 1. If f(1)<0f'( -1) < 0, f(0)>0f'(0) > 0, and f(1)<0f'(1) < 0, what can be said about the stability of y=0y=0?