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Differential Equationseasy
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An object at 100∘C100^{\circ}C100∘C cools in a room at 20∘C20^{\circ}C20∘C. The rate of cooling is dTdt=−0.1(T−20)\frac{dT}{dt} = -0.1(T - 20)dtdT​=−0.1(T−20). What is the rate of cooling at t=0t=0t=0?