Calculate the area of the surface z=x+y2z = x + y^2z=x+y2 restricted to the region 0≤x≤1,0≤y≤10 \le x \le 1, 0 \le y \le 10≤x≤1,0≤y≤1.
16(55−1)\frac{1}{6}(5\sqrt{5}-1)61(55−1)
111
5\sqrt{5}5
13(55−1)\frac{1}{3}(5\sqrt{5}-1)31(55−1)