Consider the function f(x)=∫exx2ln(t)dtf(x) = \int_{e^x}^{x^2} \ln(t) dtf(x)=∫exx2ln(t)dt. What is the expression for f′(x)f'(x)f′(x)?
2xln(x2)−exln(ex)⋅ex2x\ln(x^2) - e^x\ln(e^x) \cdot e^x2xln(x2)−exln(ex)⋅ex
2xln(x2)−exln(ex)2x\ln(x^2) - e^x\ln(e^x)2xln(x2)−exln(ex)
2x−x\frac{2}{x} - xx2−x
2xln(x2)−ex2x\ln(x^2) - e^x2xln(x2)−ex