Consider the proposition P(n):n2>nP(n): n^2 > nP(n):n2>n. For which domain is this true for all nnn?
{n∈Z∣n>1}\{n \in \mathbb{Z} \mid n > 1\}{n∈Z∣n>1}
{n∈Z∣n≥0}\{n \in \mathbb{Z} \mid n \geq 0\}{n∈Z∣n≥0}
{n∈Z∣n>−1}\{n \in \mathbb{Z} \mid n > -1\}{n∈Z∣n>−1}
The set of all integers