Consider the recurrence an=3an−1−2an−2a_n = 3a_{n-1} - 2a_{n-2}an=3an−1−2an−2 with a0=0a_0 = 0a0=0 and a1=1a_1 = 1a1=1. What is the sum a0+a1+a2a_0 + a_1 + a_2a0+a1+a2?
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