Consider the system Ax=bAx=bAx=b. If rank(A)=k\text{rank}(A) = krank(A)=k and rank(A∣b)=k+1\text{rank}(A|b) = k+1rank(A∣b)=k+1, how many solutions exist?
000
111
∞\infty∞
Depends on kkk