Consider two events EEE and FFF such that P(E)=0.4,P(F)=0.3P(E)=0.4, P(F)=0.3P(E)=0.4,P(F)=0.3, and P(E∪F)=0.6P(E \cup F)=0.6P(E∪F)=0.6. Are they mutually exclusive?
Yes
No, because P(E∩F)≠0P(E \cap F) \neq 0P(E∩F)=0
No, because P(E∪F)=P(E)+P(F)P(E \cup F) = P(E) + P(F)P(E∪F)=P(E)+P(F)
Cannot be determined