Consider y′=ex−yy' = e^x - yy′=ex−y. What is the general solution?
y=12ex+Ce−xy = \frac{1}{2}e^x + Ce^{-x}y=21ex+Ce−x
y=ex+Ce−xy = e^x + Ce^{-x}y=ex+Ce−x
y=12e−x+Cexy = \frac{1}{2}e^{-x} + Ce^xy=21e−x+Cex
y=ex+Cexy = e^x + Ce^xy=ex+Cex