Consider y′=y2/3y' = y^{2/3}y′=y2/3 with y(0)=0y(0) = 0y(0)=0. Which function is a solution?
y(x)=(x/3)3y(x) = (x/3)^3y(x)=(x/3)3
y(x)=x3/2y(x) = x^{3/2}y(x)=x3/2
y(x)=0y(x) = 0y(x)=0
All of the above