Determine the curvature κ\kappaκ of the curve y=x3y = x^3y=x3 at the point x=1x=1x=1. Formula: κ=∣f′′∣(1+(f′)2)3/2\kappa = \frac{|f''|}{(1+(f')^2)^{3/2}}κ=(1+(f′)2)3/2∣f′′∣.
1/103/21/10^{3/2}1/103/2
6/103/26/10^{3/2}6/103/2
3/103/23/10^{3/2}3/103/2
6/23/26/2^{3/2}6/23/2