Determine the general solution of the differential equation dydx=y1\slash2ex\frac{dy}{dx} = y^{1\slash 2}e^xdxdy=y1\slash2ex.
y=(12ex+C)2y = (\frac{1}{2}e^x + C)^2y=(21ex+C)2
y=(ex+C)2y = (e^x + C)^2y=(ex+C)2
y=14(ex+C)2y = \frac{1}{4}(e^x + C)^2y=41(ex+C)2
y=e2x+Cy = e^{2x} + Cy=e2x+C