Determine the general solution of the differential equation y′=4xy2y' = 4x y^2y′=4xy2.
y=−12x2+Cy = \frac{-1}{2x^2 + C}y=2x2+C−1
y=2x2+Cy = 2x^2 + Cy=2x2+C
y=Ce2x2y = Ce^{2x^2}y=Ce2x2
y=−2x2+Cy = -2x^2 + Cy=−2x2+C