Determine the general solution of the differential equation dydx=2x\frac{dy}{dx} = \frac{2}{x}dxdy=x2 for x>0x > 0x>0.
y=2x+Cy = 2x + Cy=2x+C
y=2ln(x)+Cy = 2\ln(x) + Cy=2ln(x)+C
y=x2+Cy = x^2 + Cy=x2+C
y=2x2+Cy = \frac{2}{x^2} + Cy=x22+C