Determine the general solution of y′=ex−yy' = e^x - yy′=ex−y.
y=12ex+Ce−xy = \frac{1}{2} e^x + Ce^{-x}y=21ex+Ce−x
y=ex+Ce−xy = e^x + Ce^{-x}y=ex+Ce−x
y=12ex+Cy = \frac{1}{2} e^x + Cy=21ex+C
y=e−x+Cexy = e^{-x} + Ce^xy=e−x+Cex