Determine the general solution of y′+yx=cos(x2)y' + \frac{y}{x} = \cos(x^2)y′+xy=cos(x2) for x>0x > 0x>0.
y=sin(x2)+C2xy = \frac{\sin(x^2) + C}{2x}y=2xsin(x2)+C
y=sin(x2)+Cxy = \frac{\sin(x^2) + C}{x}y=xsin(x2)+C
y=sin(x2)+Cy = \sin(x^2) + Cy=sin(x2)+C
y=cos(x2)+C2xy = \frac{\cos(x^2) + C}{2x}y=2xcos(x2)+C