Determine the horizontal asymptote of f(x)=4x2+1x+3f(x) = \frac{\sqrt{4x^2+1}}{x+3}f(x)=x+34x2+1
y=2y=2y=2 and y=−2y=-2y=−2
y=4y=4y=4
y=2y=2y=2
No horizontal asymptote