Determine the set of all real numbers xxx such that x2−9∣x∣−2≤0\frac{x^2 - 9}{|x| - 2} \leq 0∣x∣−2x2−9≤0.
(−3,−2)∪(2,3](-3, -2) \cup (2, 3](−3,−2)∪(2,3]
[−3,−2)∪(2,3][-3, -2) \cup (2, 3][−3,−2)∪(2,3]
(−3,−2)∪(2,3)(-3, -2) \cup (2, 3)(−3,−2)∪(2,3)
[−3,−2)∪(2,3)[-3, -2) \cup (2, 3)[−3,−2)∪(2,3)