Determine the set of all real values xxx such that x2−9x2+4x+3≤0\frac{x^2 - 9}{x^2 + 4x + 3} \leq 0x2+4x+3x2−9≤0.
(−3,3](-3, 3](−3,3]
[−3,3)[-3, 3)[−3,3)
(−3,−1)∪(−1,3](-3, -1) \cup (-1, 3](−3,−1)∪(−1,3]
(−3,3)(-3, 3)(−3,3)