Determine the set of values for xxx such that the inequality x2−1x2+4x+3<0\frac{x^2 - 1}{x^2 + 4x + 3} < 0x2+4x+3x2−1<0 holds.
−3<x<−1-3 < x < -1−3<x<−1
x<−3x < -3x<−3 or x>1x > 1x>1
x<−3x < -3x<−3 or x>−1x > -1x>−1
−1<x<1-1 < x < 1−1<x<1