Determine the set of xxx for ∣x2−1∣≤3|x^2 - 1| \leq 3∣x2−1∣≤3.
[−2,2][-2, 2][−2,2]
[−2,−1]∪[1,2][-2, -1] \cup [1, 2][−2,−1]∪[1,2]
[−2,2][-\sqrt{2}, \sqrt{2}][−2,2]
[−2,2]∖{0}[-2, 2] \setminus \{0\}[−2,2]∖{0}