Determine the set of xxx such that x2−2x−3x2−x−2≤0\frac{x^2-2x-3}{x^2-x-2} \leq 0x2−x−2x2−2x−3≤0.
[-1, 2]\text{[-1, 2]}[-1, 2]
(-1, 3]\text{(-1, 3]}(-1, 3]
[-1, 3] \setminus{2}\text{[-1, 3] \setminus \{2\}}[-1, 3] \setminus{2}
(-1, 2) \cup[3, \infty)\text{(-1, 2) \cup [3, \infty)}(-1, 2) \cup[3, \infty)