Determine the singular solution of y=xy′+(y′)2y = xy' + (y')^2y=xy′+(y′)2.
y=−x2/4y = -x^2/4y=−x2/4
y=−x2y = -x^2y=−x2
y=x2/4y = x^2/4y=x2/4
y=x2/2y = x^2/2y=x2/2