Determine the solution of y′=−2xyy' = -2xyy′=−2xy with y(0)=1y(0) = 1y(0)=1.
y=ex2y = e^{x^2}y=ex2
y=e−xy = e^{-x}y=e−x
y=1−x2y = 1 - x^2y=1−x2
y=e−x2y = e^{-x^2}y=e−x2