Determine the value of ∫01arcsin(x)1−x2dx\int_0^1 \frac{\arcsin(x)}{\sqrt{1-x^2}} dx∫011−x2arcsin(x)dx.
π24\frac{\pi^2}{4}4π2
π4\frac{\pi}{4}4π
111
π28\frac{\pi^2}{8}8π2