Determine the value of ∫0πsin2(x)dx\int_0^{\pi} \sin^2(x) dx∫0πsin2(x)dx using the identity sin2(x)=1−cos(2x)2\sin^2(x) = \frac{1-\cos(2x)}{2}sin2(x)=21−cos(2x).
π/2\pi/2π/2
π\piπ
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