Determine the value of ∫12x2+1x2dx\int_1^2 \frac{x^2+1}{x^2} dx∫12x2x2+1dx.
1−ln(2)1 - \ln(2)1−ln(2)
1+ln(2)1 + \ln(2)1+ln(2)
12+ln(2)\frac{1}{2} + \ln(2)21+ln(2)
222