Determine the value of ∫12xln(x)dx\int_1^2 x \ln(x) dx∫12xln(x)dx.
2ln2−0.752 \ln 2 - 0.752ln2−0.75
2ln2−342 \ln 2 - \frac{3}{4}2ln2−43
ln2−1\ln 2 - 1ln2−1
12ln2\frac{1}{2} \ln 221ln2