Determine the value of xxx such that x2−13=2\sqrt[3]{x^2 - 1} = 23x2−1=2 and x>0x > 0x>0.
x=3x = 3x=3
x=7x = \sqrt{7}x=7
x=9x = 9x=9
x=33x = 3\sqrt{3}x=33