Determine the value of xxx that satisfies the equation 1x−a−1x+a=2ax2−a2\frac{1}{x-a} - \frac{1}{x+a} = \frac{2a}{x^2-a^2}x−a1−x+a1=x2−a22a for any constant a≠0a \neq 0a=0.
All xxx such that x≠±ax \neq \pm ax=±a
Only x=ax = ax=a
No real solution
Only x=−ax = -ax=−a