Determine which of the following limits exist for the function f(x)=∣x−2∣x−2f(x) = \frac{|x-2|}{x-2}f(x)=x−2∣x−2∣ at x=2x=2x=2.
limx→2−f(x)=−1\lim_{x \to 2^-} f(x) = -1limx→2−f(x)=−1
limx→2f(x)\lim_{x \to 2} f(x)limx→2f(x) does not exist
limx→2f(x)=0\lim_{x \to 2} f(x) = 0limx→2f(x)=0
limx→2+f(x)=1\lim_{x \to 2^+} f(x) = 1limx→2+f(x)=1