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Modular Arithmetic
medium
0:00.0
Determine
x
x
x
such that
x
+
5
≡
1
(
m
o
d
7
)
x + 5 \equiv 1 \pmod 7
x
+
5
≡
1
(
mod
7
)
.
A
3
3
3
B
4
4
4
C
6
6
6
D
2
2
2
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