Does the sequence an=3⋅2na_n = 3 \cdot 2^nan=3⋅2n satisfy the recurrence an=2an−1a_n = 2a_{n-1}an=2an−1?
Yes, for all n≥0n \geq 0n≥0
No, it does not satisfy the recurrence
Yes, but only for n≥1n \geq 1n≥1
Yes, but only if a0=3a_0 = 3a0=3