Evaluate ∫(e4x−2)dx\int (e^{4x} - 2) dx∫(e4x−2)dx.
14e4x−2x+C\frac{1}{4}e^{4x} - 2x + C41e4x−2x+C
4e4x−2x+C4e^{4x} - 2x + C4e4x−2x+C
e4x−2x+Ce^{4x} - 2x + Ce4x−2x+C
14e4x−2+C\frac{1}{4}e^{4x} - 2 + C41e4x−2+C