Evaluate ∫ln(x)x2dx\int \frac{\ln(x)}{x^2} dx∫x2ln(x)dx using integration by parts.
−lnxx−1x+C-\frac{\ln x}{x} - \frac{1}{x} + C−xlnx−x1+C
lnxx+1x+C\frac{\ln x}{x} + \frac{1}{x} + Cxlnx+x1+C
−lnxx+1x+C-\frac{\ln x}{x} + \frac{1}{x} + C−xlnx+x1+C
lnxx−1x+C\frac{\ln x}{x} - \frac{1}{x} + Cxlnx−x1+C