Evaluate ∫01exex+1dx\int_0^1 \frac{e^x}{e^x+1} dx∫01ex+1exdx.
ln(e+12)\ln(\frac{e+1}{2})ln(2e+1)
e−1e-1e−1
ln(e+1)−ln(2)\ln(e+1) - \ln(2)ln(e+1)−ln(2)
ln(e+1)\ln(e+1)ln(e+1)