Evaluate ∫12x2−1xdx\int_1^2 \frac{x^2-1}{x} dx∫12xx2−1dx.
32−ln(2)\frac{3}{2} - \ln(2)23−ln(2)
12−ln(2)\frac{1}{2} - \ln(2)21−ln(2)
ln(2)−12\ln(2) - \frac{1}{2}ln(2)−21
1−ln(2)1 - \ln(2)1−ln(2)