Evaluate limn→∞1n∑k=1ncos2(kπn)\lim_{n \to \infty} \frac{1}{n} \sum_{k=1}^{n} \cos^2\left(\frac{k\pi}{n}\right)limn→∞n1∑k=1ncos2(nkπ).
000
1/21/21/2
111
π/4\pi/4π/4