Evaluate ∑n=0∞(23)n+(14)n\sum_{n=0}^{\infty} (\frac{2}{3})^n + (\frac{1}{4})^n∑n=0∞(32)n+(41)n.
13+14\frac{1}{3} + \frac{1}{4}31+41
3+43=1333 + \frac{4}{3} = \frac{13}{3}3+34=313
444
111